4n^2-8n-252=0

Solution for 4n^2-8n-252=0 equation:

4n^2-8n-252=0

a = 4; b = -8; c = -252;
Δ = b2-4ac
Δ = -82-4·4·(-252)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-64}{2*4}=\frac{-56}{8}
=-7
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+64}{2*4}=\frac{72}{8}
=9
$